Charles: [1] My first question about proton repulsion by photonic pressure would be: why don't we see the photons? [2] I thought I saw Mathis saying somewhere that all matter emits photons, all the time, as black-body radiation (I think). But BB rad is a function of temperature. So at absolute zero, there isn't any. [3] Is Mathis saying that at absolute zero, there is no Coulomb force? And that as temperature increases, so does the repulsion between protons? That just isn't correct.

[1] In which proton repulsion experiment/s were photons not detected? Did any experiment ever look for photons as the cause of repulsion?*⁶²³³

[2] I'm not clear on the definition of blackbody radiation, but I don't think Mathis ever said all matter gives off BB radiation. Maybe it does, depending on the definition anyway. But what he did say is that BB radiation is photons, which he calls the charge field, and which I often call the photonic charge field. I welcome you to post a definition of BB radiation that you favor.

[3] No. In the first following quotation, Mathis is showing that the coulomb equation is the same as the gravitational equation and both equations involve both forces, gravity and "charge". In the second quotation he explains what happens at absolute zero.

WHY THE ATOMIC WORLD IS 100 TIMES LARGER THAN WE THOUGHT http://milesmathis.com/proton.html
_The proton radius [was] arrived at by scattering experiments [] first [] done [] in 1909 [] but the theory of scattering has not changed in a century. Rutherford's equation [] is arrived at by treating the scattering as due to the Coulomb force, with the nucleus as a point-charge Ze. This equation matches data up to a certain kinetic energy, but fails after that. [] I have discovered that the math used to analyze scattering is incomplete [] rather than false because it is correct as far as it goes. It simply fails to take into account the presence of gravity at the atomic level [which is stronger than conventionally assumed at that scale]. [] Rutherford assume[d] that the force can be expressed as the Coulomb force, and that therefore it is solely an electrostatic force. I will show that this is false. []
_If the charge field is present in Newton's equation, then the gravitational field must be present in Coulomb's equation. I have shown that the two equations are really the same equation, with one hiding the charge field and the other hiding the gravitational field. When we re-expand Newton's equation, we find the charge field:
_F = GMm/r^2 = H - E = [m(A + a)] - E
_When we re-expand Coulomb's equation, we find the gravitational field:
_F = kQq/r^2 = E - H = E - [m(A + a)]
_H is the gravitational field and it is found by the same equation at all levels of size. The variable "m" is the mass of the smaller of the two objects, being the gravitating object in Newton's equation and the scattered particle in Rutherford's experiment. "A" is the gravitational acceleration of the larger object and "a" of the smaller.
_As you see, this must impact the findings of Rutherford and all scattering experiments. It will not change the data, of course, but it must change the mechanical assumptions.

Here Mathis explains why electrical conductivity increases at absolute zero. I don't know if this helps answer your question, but it should be close to an answer at least.

SUPERCONDUCTIVITY http://milesmathis.com/conduct.html
_Each particle is spinning, and this spin pulls in photons at the poles and spits them out at the equator.
_But when heat approaches absolute zero, motions slow down near a stop.
_When motions slow down, collisions decrease, and when collisions decrease, the spins cannot be maintained.
_The baryons and electrons slow their spins, and nearly stop recycling the charge field.
_Since the photons are not being sucked in, they are free to pass.
_The vortices around all particles are diminished, and the field has less resistance.
_The substance minimizes its collisions, and the charge field therefore maximizes its efficiency.
_If the charge field is carrying ions of its own, these ions will pass through the substance with minimal collision.