Charles Chandler said:
My first question about proton repulsion by photonic pressure would be: why don't we see the photons? I thought I saw Mathis saying somewhere that all matter emits photons, all the time, as black-body radiation (I think). But BB rad is a function of temperature. So at absolute zero, there isn't any. Is Mathis saying that at absolute zero, there is no Coulomb force? And that as temperature increases, so does the repulsion between protons? That just isn't correct.

 

We see them all the time, we just call them 'heat'. Miles has calculated that the charge field should peak in the infrared and that's exactly what we see. Heat is photons, a higher temperature means more photons and more energetic photons. The charge field is also what fills up the missing 95% of matter that dark matter/energy are supposed to fill. He has shown that a proton emits 19X its own mass every second. Since the proton is main constituent of all matter and 19/20 is 95%, he has a match. We just need to give photons extension and mass and the dark matter mystery is solved.

 

Absolute zero is a limit and not an achievable temperature. So long as you have matter, you will have some limited charge field recycling and therefore some emission and there will always be the associated forces (E/M) if the charge field is present.

 

Proton repulsion would need to be defined more carefulyy to correctly analyze. Are we talking repulsion between free protons, or repulsion with the elemental structure? One will be governed by the ambient charge field and the other will be governed by the resultant charge field through the nuclear structure itself. They are both caused by the same thing, but will behave differently due to the other influences around. Proton repulsion within the nuclear structure will not be subject to temperature fluctuations I don't believe; rather the increased heat (charge field) that is funneled through the structure will eventually blow the structure apart (aka fission).